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(F)=F2-49
We move all terms to the left:
(F)-(F2-49)=0
We add all the numbers together, and all the variables
-(+F^2-49)+F=0
We get rid of parentheses
-F^2+F+49=0
We add all the numbers together, and all the variables
-1F^2+F+49=0
a = -1; b = 1; c = +49;
Δ = b2-4ac
Δ = 12-4·(-1)·49
Δ = 197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{197}}{2*-1}=\frac{-1-\sqrt{197}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{197}}{2*-1}=\frac{-1+\sqrt{197}}{-2} $
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