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(F)=F2-4F+1
We move all terms to the left:
(F)-(F2-4F+1)=0
We add all the numbers together, and all the variables
-(+F^2-4F+1)+F=0
We get rid of parentheses
-F^2+4F+F-1=0
We add all the numbers together, and all the variables
-1F^2+5F-1=0
a = -1; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·(-1)·(-1)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{21}}{2*-1}=\frac{-5-\sqrt{21}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{21}}{2*-1}=\frac{-5+\sqrt{21}}{-2} $
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