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(F)=F2-4F-8
We move all terms to the left:
(F)-(F2-4F-8)=0
We add all the numbers together, and all the variables
-(+F^2-4F-8)+F=0
We get rid of parentheses
-F^2+4F+F+8=0
We add all the numbers together, and all the variables
-1F^2+5F+8=0
a = -1; b = 5; c = +8;
Δ = b2-4ac
Δ = 52-4·(-1)·8
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{57}}{2*-1}=\frac{-5-\sqrt{57}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{57}}{2*-1}=\frac{-5+\sqrt{57}}{-2} $
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