F(x)=x2-4x/20

Solution for F(x)=x2-4x/20 equation:

(F)=F2-4F/20

We move all terms to the left:

(F)-(F2-4F/20)=0

We add all the numbers together, and all the variables

-(+F^2-4F/20)+F=0

We get rid of parentheses

-F^2+4F/20+F=0

We multiply all the terms by the denominator


-F^2*20+4F+F*20=0

Wy multiply elements

-20F^2+4F+20F=0

We add all the numbers together, and all the variables

-20F^2+24F=0

a = -20; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-20)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-20}=\frac{-48}{-40}
=1+1/5
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-20}=\frac{0}{-40}
=0
$