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(F)=F2-6.5
We move all terms to the left:
(F)-(F2-6.5)=0
We add all the numbers together, and all the variables
-(+F^2-6.5)+F=0
We get rid of parentheses
-F^2+F+6.5=0
We add all the numbers together, and all the variables
-1F^2+F+6.5=0
a = -1; b = 1; c = +6.5;
Δ = b2-4ac
Δ = 12-4·(-1)·6.5
Δ = 27
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{27}=\sqrt{9*3}=\sqrt{9}*\sqrt{3}=3\sqrt{3}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3\sqrt{3}}{2*-1}=\frac{-1-3\sqrt{3}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3\sqrt{3}}{2*-1}=\frac{-1+3\sqrt{3}}{-2} $
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