F(x+1)=3(x+1)+2

Solution for F(x+1)=3(x+1)+2 equation:

(F+1)=3(F+1)+2

We move all terms to the left:

(F+1)-(3(F+1)+2)=0

We get rid of parentheses

F-(3(F+1)+2)+1=0


We calculate terms in parentheses: -(3(F+1)+2), so:

3(F+1)+2

We multiply parentheses

3F+3+2

We add all the numbers together, and all the variables

3F+5

Back to the equation:

-(3F+5)


We get rid of parentheses

F-3F-5+1=0

We add all the numbers together, and all the variables

-2F-4=0

We move all terms containing F to the left, all other terms to the right

-2F=4

F=4/-2

F=-2