F(x+1)=4(x+1)+5

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Solution for F(x+1)=4(x+1)+5 equation: 



(F+1)=4(F+1)+5

We move all terms to the left:

(F+1)-(4(F+1)+5)=0

We get rid of parentheses

F-(4(F+1)+5)+1=0



We calculate terms in parentheses: -(4(F+1)+5), so:

4(F+1)+5

We multiply parentheses

4F+4+5

We add all the numbers together, and all the variables

4F+9

Back to the equation:

-(4F+9)



We get rid of parentheses

F-4F-9+1=0

We add all the numbers together, and all the variables

-3F-8=0

We move all terms containing F to the left, all other terms to the right

-3F=8

F=8/-3

F=-2+2/3

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