F(x+2)=3(x+2)-4

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Solution for F(x+2)=3(x+2)-4 equation: 



(F+2)=3(F+2)-4

We move all terms to the left:

(F+2)-(3(F+2)-4)=0

We get rid of parentheses

F-(3(F+2)-4)+2=0



We calculate terms in parentheses: -(3(F+2)-4), so:

3(F+2)-4

We multiply parentheses

3F+6-4

We add all the numbers together, and all the variables

3F+2

Back to the equation:

-(3F+2)



We get rid of parentheses

F-3F-2+2=0

We add all the numbers together, and all the variables

-2F=0

F=0/-2

F=0

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