F(x+2)=3(x+2)-6

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Solution for F(x+2)=3(x+2)-6 equation: 



(F+2)=3(F+2)-6

We move all terms to the left:

(F+2)-(3(F+2)-6)=0

We get rid of parentheses

F-(3(F+2)-6)+2=0



We calculate terms in parentheses: -(3(F+2)-6), so:

3(F+2)-6

We multiply parentheses

3F+6-6

We add all the numbers together, and all the variables

3F

Back to the equation:

-(3F)



We add all the numbers together, and all the variables

-2F+2=0

We move all terms containing F to the left, all other terms to the right

-2F=-2

F=-2/-2

F=1

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