F(x+3)=7(x+3)+6(x+3)+5

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Solution for F(x+3)=7(x+3)+6(x+3)+5 equation: 



(F+3)=7(F+3)+6(F+3)+5

We move all terms to the left:

(F+3)-(7(F+3)+6(F+3)+5)=0

We get rid of parentheses

F-(7(F+3)+6(F+3)+5)+3=0



We calculate terms in parentheses: -(7(F+3)+6(F+3)+5), so:

7(F+3)+6(F+3)+5

We multiply parentheses

7F+6F+21+18+5

We add all the numbers together, and all the variables

13F+44

Back to the equation:

-(13F+44)



We get rid of parentheses

F-13F-44+3=0

We add all the numbers together, and all the variables

-12F-41=0

We move all terms containing F to the left, all other terms to the right

-12F=41

F=41/-12

F=-3+5/12

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