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/F=3F-4
We move all terms to the left:
/F-(3F-4)=0
Domain of the equation: F!=0We get rid of parentheses
F∈R
/F-3F+4=0
We multiply all the terms by the denominator
-3F*F+4*F+=0
We add all the numbers together, and all the variables
4F-3F*F=0
Wy multiply elements
-3F^2+4F=0
a = -3; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-3)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-3}=\frac{-8}{-6} =1+1/3 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-3}=\frac{0}{-6} =0 $
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