F5(3x+4)-2x=7x-3(2x+11)

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Solution for F5(3x+4)-2x=7x-3(2x+11) equation:



5(3F+4)-2F=7F-3(2F+11)
We move all terms to the left:
5(3F+4)-2F-(7F-3(2F+11))=0
We add all the numbers together, and all the variables
-2F+5(3F+4)-(7F-3(2F+11))=0
We multiply parentheses
-2F+15F-(7F-3(2F+11))+20=0
We calculate terms in parentheses: -(7F-3(2F+11)), so:
7F-3(2F+11)
We multiply parentheses
7F-6F-33
We add all the numbers together, and all the variables
F-33
Back to the equation:
-(F-33)
We add all the numbers together, and all the variables
13F-(F-33)+20=0
We get rid of parentheses
13F-F+33+20=0
We add all the numbers together, and all the variables
12F+53=0
We move all terms containing F to the left, all other terms to the right
12F=-53
F=-53/12
F=-4+5/12

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