F=(1/9)(k)(d-n)

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Solution for F=(1/9)(k)(d-n) equation: 


x in (-oo:+oo)

F = (1/9)*k*(d-n) // - (1/9)*k*(d-n)

F-((1/9)*k*(d-n)) = 0

(-1/9)*k*(d-n)+F = 0

F-1/9*k*(d-n) = 0

F-1/9*k*(d-n) = 0

F-1/9*d*k+1/9*k*n = 0

F-1/9*d*k+1/9*k*n = 0

x belongs to the empty set

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