F=9/5(n-57)

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Solution for F=9/5(n-57) equation:



=9/5(F-57)
We move all terms to the left:
-(9/5(F-57))=0
Domain of the equation: 5(F-57))!=0
F∈R
We multiply all the terms by the denominator
-(9=0
We add all the numbers together, and all the variables
=0
F=0/1
F=0

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