F=9/5(n-99)

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Solution for F=9/5(n-99) equation: 



=9/5(F-99)

We move all terms to the left:

-(9/5(F-99))=0



Domain of the equation: 5(F-99))!=0

F∈R



We multiply all the terms by the denominator


-(9=0

We add all the numbers together, and all the variables

=0

F=0/1

F=0

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