F=9/5c+25

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Solution for F=9/5c+25 equation: 



=9/5F+25

We move all terms to the left:

-(9/5F+25)=0



Domain of the equation: 5F+25)!=0

F∈R



We get rid of parentheses

-9/5F-25=0

We multiply all the terms by the denominator


-25*5F-9=0

Wy multiply elements

-125F-9=0

We move all terms containing F to the left, all other terms to the right

-125F=9

F=9/-125

F=-9/125

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