F=9/5c+32)

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Solution for F=9/5c+32) equation:



=9/5F+32)
We move all terms to the left:
-(9/5F+32))=0
Domain of the equation: 5F+32))!=0
F∈R
We get rid of parentheses
-9/5F-32)=0
We multiply all the terms by the denominator
-32)*5F-9=0
F=0/1
F=0

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