G(g-2)+g=6(g-4)

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Solution for G(g-2)+g=6(g-4) equation: 



(G-2)+G=6(G-4)

We move all terms to the left:

(G-2)+G-(6(G-4))=0

We add all the numbers together, and all the variables

G+(G-2)-(6(G-4))=0

We get rid of parentheses

G+G-(6(G-4))-2=0



We calculate terms in parentheses: -(6(G-4)), so:

6(G-4)

We multiply parentheses

6G-24

Back to the equation:

-(6G-24)



We add all the numbers together, and all the variables

2G-(6G-24)-2=0

We get rid of parentheses

2G-6G+24-2=0

We add all the numbers together, and all the variables

-4G+22=0

We move all terms containing G to the left, all other terms to the right

-4G=-22

G=-22/-4

G=5+1/2

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