G(t-2)=3t2-5t+5

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Solution for G(t-2)=3t2-5t+5 equation: 



(G-2)=3G^2-5G+5

We move all terms to the left:

(G-2)-(3G^2-5G+5)=0

We get rid of parentheses

-3G^2+G+5G-2-5=0

We add all the numbers together, and all the variables

-3G^2+6G-7=0

a = -3; b = 6; c = -7;
Δ = b2-4ac
Δ = 62-4·(-3)·(-7)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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