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(G)=(5G-3)/G
We move all terms to the left:
(G)-((5G-3)/G)=0
Domain of the equation: G)!=0We multiply all the terms by the denominator
G!=0/1
G!=0
G∈R
G*G)-((5G-3)=0
Wy multiply elements
G^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$G=\frac{-b}{2a}=\frac{0}{2}=0$
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