G(x)=-2/5x-2

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Solution for G(x)=-2/5x-2 equation:



(G)=-2/5G-2
We move all terms to the left:
(G)-(-2/5G-2)=0
Domain of the equation: 5G-2)!=0
G∈R
We get rid of parentheses
G+2/5G+2=0
We multiply all the terms by the denominator
G*5G+2*5G+2=0
Wy multiply elements
5G^2+10G+2=0
a = 5; b = 10; c = +2;
Δ = b2-4ac
Δ = 102-4·5·2
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{15}}{2*5}=\frac{-10-2\sqrt{15}}{10} $
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{15}}{2*5}=\frac{-10+2\sqrt{15}}{10} $

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