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(G)=-9/5G-8
We move all terms to the left:
(G)-(-9/5G-8)=0
Domain of the equation: 5G-8)!=0We get rid of parentheses
G∈R
G+9/5G+8=0
We multiply all the terms by the denominator
G*5G+8*5G+9=0
Wy multiply elements
5G^2+40G+9=0
a = 5; b = 40; c = +9;
Δ = b2-4ac
Δ = 402-4·5·9
Δ = 1420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1420}=\sqrt{4*355}=\sqrt{4}*\sqrt{355}=2\sqrt{355}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{355}}{2*5}=\frac{-40-2\sqrt{355}}{10} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{355}}{2*5}=\frac{-40+2\sqrt{355}}{10} $
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