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(G)=20/G-3
We move all terms to the left:
(G)-(20/G-3)=0
Domain of the equation: G-3)!=0We get rid of parentheses
G∈R
G-20/G+3=0
We multiply all the terms by the denominator
G*G+3*G-20=0
We add all the numbers together, and all the variables
3G+G*G-20=0
Wy multiply elements
G^2+3G-20=0
a = 1; b = 3; c = -20;
Δ = b2-4ac
Δ = 32-4·1·(-20)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{89}}{2*1}=\frac{-3-\sqrt{89}}{2} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{89}}{2*1}=\frac{-3+\sqrt{89}}{2} $
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