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(G)=2G^2-4G+12
We move all terms to the left:
(G)-(2G^2-4G+12)=0
We get rid of parentheses
-2G^2+G+4G-12=0
We add all the numbers together, and all the variables
-2G^2+5G-12=0
a = -2; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·(-2)·(-12)
Δ = -71
Delta is less than zero, so there is no solution for the equation
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