G(x)=33/5x+55

Solution for G(x)=33/5x+55 equation:

(G)=33/5G+55

We move all terms to the left:

(G)-(33/5G+55)=0


Domain of the equation: 5G+55)!=0

G∈R


We get rid of parentheses

G-33/5G-55=0

We multiply all the terms by the denominator


G*5G-55*5G-33=0

Wy multiply elements

5G^2-275G-33=0

a = 5; b = -275; c = -33;
Δ = b2-4ac
Δ = -2752-4·5·(-33)
Δ = 76285
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-275)-\sqrt{76285}}{2*5}=\frac{275-\sqrt{76285}}{10}
$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-275)+\sqrt{76285}}{2*5}=\frac{275+\sqrt{76285}}{10}
$