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(G)=4/G-6+5
We move all terms to the left:
(G)-(4/G-6+5)=0
Domain of the equation: G-6+5)!=0We add all the numbers together, and all the variables
We move all terms containing G to the left, all other terms to the right
G+5)!=6
G∈R
G-(4/G-1)=0
We get rid of parentheses
G-4/G+1=0
We multiply all the terms by the denominator
G*G+1*G-4=0
We add all the numbers together, and all the variables
G+G*G-4=0
Wy multiply elements
G^2+G-4=0
a = 1; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·1·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{17}}{2*1}=\frac{-1-\sqrt{17}}{2} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{17}}{2*1}=\frac{-1+\sqrt{17}}{2} $
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