G=a(a-9)+9a

Solution for G=a(a-9)+9a equation:

=G(G-9)+9G

We move all terms to the left:

-(G(G-9)+9G)=0


We calculate terms in parentheses: -(G(G-9)+9G), so:

G(G-9)+9G

We add all the numbers together, and all the variables

9G+G(G-9)

We multiply parentheses

G^2+9G-9G

We add all the numbers together, and all the variables

G^2

Back to the equation:

-(G^2)


We add all the numbers together, and all the variables

-1G^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$G=\frac{-b}{2a}=\frac{0}{-2}=0$