H(a+1)=2(a+1)+10

Solution for H(a+1)=2(a+1)+10 equation:

(H+1)=2(H+1)+10

We move all terms to the left:

(H+1)-(2(H+1)+10)=0

We get rid of parentheses

H-(2(H+1)+10)+1=0


We calculate terms in parentheses: -(2(H+1)+10), so:

2(H+1)+10

We multiply parentheses

2H+2+10

We add all the numbers together, and all the variables

2H+12

Back to the equation:

-(2H+12)


We get rid of parentheses

H-2H-12+1=0

We add all the numbers together, and all the variables

-1H-11=0

We move all terms containing H to the left, all other terms to the right

-H=11

H=11/-1

H=-11