If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(H)=-16H*16H+120H+10
We move all terms to the left:
(H)-(-16H*16H+120H+10)=0
We add all the numbers together, and all the variables
H-(120H-16H*16H+10)=0
We get rid of parentheses
H-120H+16H*16H-10=0
We add all the numbers together, and all the variables
-119H+16H*16H-10=0
Wy multiply elements
256H^2-119H-10=0
a = 256; b = -119; c = -10;
Δ = b2-4ac
Δ = -1192-4·256·(-10)
Δ = 24401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-119)-\sqrt{24401}}{2*256}=\frac{119-\sqrt{24401}}{512} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-119)+\sqrt{24401}}{2*256}=\frac{119+\sqrt{24401}}{512} $
| 25(z−2)=125 | | 1/2(3x+4)=4 | | 12-7c/6=-4 | | r^2+12r-3=0 | | 7x+159=8x-700 | | 65=5v+10 | | O=4+n/5 | | 6-20+y/3=1 | | 37=6r−11 | | 8y-6=6 | | −8=−12−4t | | 5x+2-2=15 | | 6(2y-1)-2(2y=6 | | 3y−1=23 | | b*b=16/121 | | 12x+4+30=10x-10 | | 0.18r+19=20 | | 104=x(x-3)/2 | | 12x+4+10x-10=30 | | q+17=-8 | | 104=x(x-3) | | 2(x^2-3)^3=0 | | 9x^2-42x-72=0 | | 7x159=8x-700 | | x+3=10-5/3 | | 24–3m=5m | | -(6b+7)+8=-19 | | (3x^2-2x-7=0 | | X+2x+3(x+2x)=144 | | (3x^2-2x-7)(3x^2-2x+1)=0 | | 420.4=52.55n | | 7x-26=23 |