H(t)=16(t2)+225

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Solution for H(t)=16(t2)+225 equation: 



(H)=16(H2)+225

We move all terms to the left:

(H)-(16(H2)+225)=0

We add all the numbers together, and all the variables

-(+16H^2+225)+H=0

We get rid of parentheses

-16H^2+H-225=0

a = -16; b = 1; c = -225;
Δ = b2-4ac
Δ = 12-4·(-16)·(-225)
Δ = -14399
Delta is less than zero, so there is no solution for the equation

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