H(x)=(5x+8)(2x+4)

Solution for H(x)=(5x+8)(2x+4) equation:

(H)=(5H+8)(2H+4)

We move all terms to the left:

(H)-((5H+8)(2H+4))=0

We multiply parentheses ..

-((+10H^2+20H+16H+32))+H=0


We calculate terms in parentheses: -((+10H^2+20H+16H+32)), so:

(+10H^2+20H+16H+32)

We get rid of parentheses

10H^2+20H+16H+32

We add all the numbers together, and all the variables

10H^2+36H+32

Back to the equation:

-(10H^2+36H+32)


We add all the numbers together, and all the variables

H-(10H^2+36H+32)=0

We get rid of parentheses

-10H^2+H-36H-32=0

We add all the numbers together, and all the variables

-10H^2-35H-32=0

a = -10; b = -35; c = -32;
Δ = b2-4ac
Δ = -352-4·(-10)·(-32)
Δ = -55
Delta is less than zero, so there is no solution for the equation