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(H)=-H2-6H-9
We move all terms to the left:
(H)-(-H2-6H-9)=0
We add all the numbers together, and all the variables
-(-1H^2-6H-9)+H=0
We get rid of parentheses
1H^2+6H+H+9=0
We add all the numbers together, and all the variables
H^2+7H+9=0
a = 1; b = 7; c = +9;
Δ = b2-4ac
Δ = 72-4·1·9
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{13}}{2*1}=\frac{-7-\sqrt{13}}{2} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{13}}{2*1}=\frac{-7+\sqrt{13}}{2} $
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