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(H)=3H^2+7
We move all terms to the left:
(H)-(3H^2+7)=0
We get rid of parentheses
-3H^2+H-7=0
a = -3; b = 1; c = -7;
Δ = b2-4ac
Δ = 12-4·(-3)·(-7)
Δ = -83
Delta is less than zero, so there is no solution for the equation
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