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(H)=5H^2-30H+30
We move all terms to the left:
(H)-(5H^2-30H+30)=0
We get rid of parentheses
-5H^2+H+30H-30=0
We add all the numbers together, and all the variables
-5H^2+31H-30=0
a = -5; b = 31; c = -30;
Δ = b2-4ac
Δ = 312-4·(-5)·(-30)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-19}{2*-5}=\frac{-50}{-10} =+5 $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+19}{2*-5}=\frac{-12}{-10} =1+1/5 $
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