H/2h+4-1/h+2=1

Solution for H/2h+4-1/h+2=1 equation:

/2H+4-1/H+2=1

We move all terms to the left:

/2H+4-1/H+2-(1)=0


Domain of the equation: 2H!=0

H!=0/2

H!=0

H∈R



Domain of the equation: H!=0

H∈R


We add all the numbers together, and all the variables

/2H-1/H+5=0

We calculate fractions


H/2H^2+(-2H)/2H^2+5=0

We multiply all the terms by the denominator


H+(-2H)+5*2H^2=0

Wy multiply elements

10H^2+H+(-2H)=0

We get rid of parentheses

10H^2+H-2H=0

We add all the numbers together, and all the variables

10H^2-1H=0

a = 10; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·10·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*10}=\frac{0}{20}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*10}=\frac{2}{20}
=1/10
$