H=(2x+9)L=(5x-3)W=(3x+2)V=7106

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Solution for H=(2x+9)L=(5x-3)W=(3x+2)V=7106 equation: 



=(2H+9)=(5H-3)=(3H+2)=7106

We move all terms to the left:

-((2H+9))=0



We calculate terms in parentheses: -((2H+9)), so:

(2H+9)

We get rid of parentheses

2H+9

Back to the equation:

-(2H+9)



We get rid of parentheses

-2H-9=0

We move all terms containing H to the left, all other terms to the right

-2H=9

H=9/-2

H=-4+1/2

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