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=-0.002H^2=0.36H
We move all terms to the left:
-(-0.002H^2)=0
We get rid of parentheses
0.002H^2=0
a = 0.002; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·0.002·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$H=\frac{-b}{2a}=\frac{0}{0.004}=0$
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