H=-16t2+36

Solution for H=-16t2+36 equation:

=-16H^2+36

We move all terms to the left:

-(-16H^2+36)=0

We get rid of parentheses

16H^2-36=0

a = 16; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·16·(-36)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*16}=\frac{-48}{32}
=-1+1/2
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*16}=\frac{48}{32}
=1+1/2
$