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=-4.9H^2+18H+.8
We move all terms to the left:
-(-4.9H^2+18H+.8)=0
We get rid of parentheses
4.9H^2-18H-.8=0
We add all the numbers together, and all the variables
4.9H^2-18H-0.8=0
a = 4.9; b = -18; c = -0.8;
Δ = b2-4ac
Δ = -182-4·4.9·(-0.8)
Δ = 339.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-\sqrt{339.68}}{2*4.9}=\frac{18-\sqrt{339.68}}{9.8} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+\sqrt{339.68}}{2*4.9}=\frac{18+\sqrt{339.68}}{9.8} $
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