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=-4.9H^2+2.07H
We move all terms to the left:
-(-4.9H^2+2.07H)=0
We get rid of parentheses
4.9H^2-2.07H=0
a = 4.9; b = -2.07; c = 0;
Δ = b2-4ac
Δ = -2.072-4·4.9·0
Δ = 4.2849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.07)-\sqrt{4.2849}}{2*4.9}=\frac{2.07-\sqrt{4.2849}}{9.8} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.07)+\sqrt{4.2849}}{2*4.9}=\frac{2.07+\sqrt{4.2849}}{9.8} $
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