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=-4.9H^2+80H+220
We move all terms to the left:
-(-4.9H^2+80H+220)=0
We get rid of parentheses
4.9H^2-80H-220=0
a = 4.9; b = -80; c = -220;
Δ = b2-4ac
Δ = -802-4·4.9·(-220)
Δ = 10712
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10712}=\sqrt{4*2678}=\sqrt{4}*\sqrt{2678}=2\sqrt{2678}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{2678}}{2*4.9}=\frac{80-2\sqrt{2678}}{9.8} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{2678}}{2*4.9}=\frac{80+2\sqrt{2678}}{9.8} $
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