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=16H^2+
We move all terms to the left:
-(16H^2+)=0
We get rid of parentheses
-16H^2-=0
We add all the numbers together, and all the variables
-16H^2=0
a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:H=\frac{-b}{2a}=\frac{0}{-32}=0
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