H=16t2+68t+60

Solution for H=16t2+68t+60 equation:

=16H^2+68H+60

We move all terms to the left:

-(16H^2+68H+60)=0

We get rid of parentheses

-16H^2-68H-60=0

a = -16; b = -68; c = -60;
Δ = b2-4ac
Δ = -682-4·(-16)·(-60)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-28}{2*-16}=\frac{40}{-32}
=-1+1/4
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+28}{2*-16}=\frac{96}{-32}
=-3
$