H=2(x-5)

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Solution for H=2(x-5) equation: 



=2(H-5)

We move all terms to the left:

-(2(H-5))=0



We calculate terms in parentheses: -(2(H-5)), so:

2(H-5)

We multiply parentheses

2H-10

Back to the equation:

-(2H-10)



We get rid of parentheses

-2H+10=0

We move all terms containing H to the left, all other terms to the right

-2H=-10

H=-10/-2

H=+5

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