H=2/3(a+2b)

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Solution for H=2/3(a+2b) equation: 


x in (-oo:+oo)

H = (2/3)*(a+2*b) // - (2/3)*(a+2*b)

H-((2/3)*(a+2*b)) = 0

(-2/3)*(a+2*b)+H = 0

H-2/3*(a+2*b) = 0

H-2/3*(a+2*b) = 0

H-2/3*a-4/3*b = 0

H-2/3*a-4/3*b = 0

x belongs to the empty set

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