H=2/3(k-5)

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Solution for H=2/3(k-5) equation: 


x in (-oo:+oo)

H = (2/3)*(k-5) // - (2/3)*(k-5)

H-((2/3)*(k-5)) = 0

(-2/3)*(k-5)+H = 0

H-2/3*(k-5) = 0

H-2/3*(k-5) = 0

H-2/3*k+10/3 = 0

H-2/3*k+10/3 = 0

x belongs to the empty set

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