H=201t-16t2

Solution for H=201t-16t2 equation:

=201H-16H^2

We move all terms to the left:

-(201H-16H^2)=0

We get rid of parentheses

16H^2-201H=0

a = 16; b = -201; c = 0;
Δ = b2-4ac
Δ = -2012-4·16·0
Δ = 40401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40401}=201$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-201)-201}{2*16}=\frac{0}{32}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-201)+201}{2*16}=\frac{402}{32}
=12+9/16
$