H=3/5t+12

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Solution for H=3/5t+12 equation: 



=3/5H+12

We move all terms to the left:

-(3/5H+12)=0



Domain of the equation: 5H+12)!=0

H∈R



We get rid of parentheses

-3/5H-12=0

We multiply all the terms by the denominator


-12*5H-3=0

Wy multiply elements

-60H-3=0

We move all terms containing H to the left, all other terms to the right

-60H=3

H=3/-60

H=-1/20

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