H=4.9t2+24t+1.2

Solution for H=4.9t2+24t+1.2 equation:

=4.9H^2+24H+1.2

We move all terms to the left:

-(4.9H^2+24H+1.2)=0

We get rid of parentheses

-4.9H^2-24H-1.2=0

a = -4.9; b = -24; c = -1.2;
Δ = b2-4ac
Δ = -242-4·(-4.9)·(-1.2)
Δ = 552.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{552.48}}{2*-4.9}=\frac{24-\sqrt{552.48}}{-9.8}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{552.48}}{2*-4.9}=\frac{24+\sqrt{552.48}}{-9.8}
$