I(16x+22)=6x+23

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Solution for I(16x+22)=6x+23 equation: 



(16I+22)=6I+23

We move all terms to the left:

(16I+22)-(6I+23)=0

We get rid of parentheses

16I-6I+22-23=0

We add all the numbers together, and all the variables

10I-1=0

We move all terms containing I to the left, all other terms to the right

10I=1

I=1/10

I=1/10

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